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Hydrogen atom in ground state is excited...

Hydrogen atom in ground state is excited by a monochromatic radiation of `lambda = 975 Å`. Number of spectral lines in the resulting spectrum emitted will be

A

3

B

2

C

6

D

10

Text Solution

Verified by Experts

The correct Answer is:
A

Energy provided to the ground state electron
`=(hc)/(lambda)=(6.6xx10^(-34)xx3xx10^(8))/(975xx10^(-10))=(6.6xx3)/(975)xx10^(-16)`
`=0.020xx10^(-16)=2xx10^(-18)J=(20xx10^(-19))/(1.6xx10^(-19))eV`
`=(20)/(1.6)=12.5eV`
It means the electron is jump to n=3 from n=1
The number of possible spectral lines from n=3 to n=1 is 3
`{:(i.e.,(n=3),rarr,(n=1)),(,(n=3),rarr,(n=2)),("and",(n=2),rarr,(n=1)):}`
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