An electron of a stationary hydrogen atom passes from the fifith energy level to the ground level. The velocity of hydrogen atom aciquired as a result of photon emission will be

Options

A. `(24hR)/(25m)`
B. `(25hR)/(24m)`
C. `(25m)/(24hR)`
D. `(24m)/(25hR)`

Answer

A

Explanation

Hence, `E_(5)-E_(1)=(hc)/(lambda)`
and `(Rhc)/(25)-Rhc=(hc)/(lambda)rArr(24)/(25)R=(1)/(lambda)`
But `p=(hc)/(lambda)anv=(h)/(mlambda)=(24)/(25)(Rhc)/(m)`