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calculate the mass defect of Helium ...

calculate the mass defect of Helium `[""._(2)He^(4)]`
mass of proton `=1.007276 u,`
Mass of neutron `=1.008665u,`
Mass of `""._(2) He^(4)= 1.001506 u,`

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To calculate the mass defect of Helium-4 \((\text{He}^{4}_{2})\), we will follow these steps: ### Step 1: Identify the number of protons and neutrons in Helium-4 Helium-4 has: - Atomic number (number of protons) = 2 - Mass number = 4 To find the number of neutrons: ...
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Calculate : (i) mass defect of Helium (""_(2)^(4)He) nucleus (ii) Obtain a relation between radius and mass number of a nucleus. Mass of proton = 1.007276 u Mass of neutron = 1.008665 u Mass of ""_(2)He^(4) nucleus = 4.001506 u (b) What are characteristic X-rays ? How are they different from continuous X-rays Give any one difference.

Calculate the binding energy of an alpha -particle in MeV Given : m_(p) (mass of proton) = 1.007825 amu, m_(n) (mass of neutron) = 1.008665 amu Mass of the nucleus =4.002800 amu, 1 amu = 931 MeV.

Calculate the binding energy of an alpha particle from the following data: mass of _1^1H atom = 1.007825 u mass of neutron = 1.008665 u mass of _4^2He atom = 4.00260 u Take 1 u = 931 MeV c^(-2)

Calculate binding energy of oxygen nucleus (""_(8)^(16)O) from the data given below: Mass of a proton m_(p) = 1.007825u Mass of neutron m_(n) = 1.008665u Mass of (""_(8)^(16)O)m_(o) = 15.994915 u

What is the binding energy per nucleon in ._2He^4 Given , Mass of ._2He^4 =4.002604 amu Mass of proton =1.007825 amu Mass of neutron =1.008665 amu

What is the binding energy per nucleon in ._2He^4 Given , Mass of ._2He^4 =4.002604 amu Mass of proton =1.007825 amu Mass of neutron =1.008665 amu

Calculate the binding energy per nucleon of ._(20)^(40)Ca . Given that mass of ._(20)^(40)Ca nucleus = 39.962589 u , mass of proton = 1.007825 u . Mass of Neutron = 1.008665 u and 1 u is equivalent to 931 MeV .

Calculate the binding energy per nucleon of ._17^35Cl nucleus. Given that mass of ._17^35Cl nucleus = 34.98000 u, mass of proton = 1.007825 u, mass of neutron = 1.008665 u and 1 u is equivalent to 931 Mev.

What would be the energy required to dissociate completely 1 g of Ca-40 into its constituent, particles? Given: Mass of proton =1.00866 am u , Mass of neutron =1.00866 am u , Mass of Ca-40 =39.97454 am u , (Take 1 am u =931 MeV ).

Find the Binding energy per neucleon for ""_(50)^(120)Sn Mass of proton m_(p)=1.00783U , mass of neutron m_(n)=1.00867U and mass of tin nucleus m_(Sn)=119.902199U . (take 1 U = 931 MEV)

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