A neutron breaks into a proton and electorn. Calculate the eenrgy produced in this reaction in `m_(e) = 9 xx 10^(-31) kg, m_(p) = 1.6725 xx 10^(-27) kg, m_(n) = 1.6747 xx 10^(-27) kg, c = 3xx10^(8)m//sec`.

Explanation

We have `""_(0)^(1)n to ""_(1)^(1) p+""_(-1)^(0)e`
Mass defect ,`Delta m=m _(n) -m_(p) -m_(e)`
`=[1.6747xx10^(-27)-1.6724xx10^(-27)-0.0009xx10^(-27)]`
`=1.3xx10^(-30)`kg
Energy produced `= Delta mc^(2)= 1.3xx10^(-30)xx(3xx10)^(8) ^(2)`
`=11.7xx10^(-14)J =(11.7xx10^(-14))/(1.6xx10^(-13))=0.73 MeV`
`(:' 1 Me V =1.6xx10^(130J)`