if the binding energy per nucleon of deuteron is 1.115 Me V , find its masss defect in atomic mass unit .

Explanation

Binding energy per nucleon is `E_(bn) =(e_(b))/(A)`
for seuteron , atomic mass ,A=2
sibstuting the values in above equation ,
` therefore 1.115 Me V =( e_(b))/(2) `
`E_(b) = xx1.115implies E_(b) =Delta Mc^(2)implies Delta m =(E_(b))/(C^(2))`
Mass defect , `Delta M=(2xx1.115)/(931.5)u =0.0024 u`