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Find the amount of energy released when `1` atom of Uranium `._(92)U^(235)(235.0439 "amu")` undergoes fission by slow neturon `(1.0087 "amu")` and is splitted into Krypton `._(36)Kr^(92)(91.8973 "amu")` and Barium `._(56)Br^(141)(140.9139 "amu")` assuming no energy is lost. Hence find the enrgy in `kWh`, when `1g` of it undergoes fission.

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To solve the problem step by step, we will calculate the energy released during the fission of one atom of Uranium-235 and then find the total energy released when 1 gram of Uranium-235 undergoes fission. ### Step 1: Write the Fission Reaction The fission of Uranium-235 by a neutron can be represented as follows: \[ ^{235}_{92}U + ^1_0n \rightarrow ^{92}_{36}Kr + ^{141}_{56}Ba + \text{Energy} \] ...
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The number of neutrons released when ._92 U^235 undergoes fission by absorbing ._0 n^1 and (._56 Ba^144 + ._36 Kr^89) are formed, is.

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When slow neutrons are incident on a target containing underset(92)overset(235).U , a possible fission reaction is underset(92)overset(235).U+underset(0)overset(1).nrarr underset(56)overset(141).Ba+underset(36)overset(92).Kr+3_(0)^(1)n Estimate the amount of energy released using the following data Given, mass of underset(92)overset(235).U=235.04 amu , mass of underset(0)overset(1).n=1.0087 amu , mass of underset(56)overset(141).Ba=140.91 amu , mass of underset(36)overset(92).Kr=91.926 amu , and energy equivalent to 1 amu=931 MeV.

The ._(92)U^(235) absorbs a slow neturon (thermal neutron) & undergoes a fission represented by ._(92)U^(235)+._(0)n^(1)rarr._(92)U^(236)rarr._(56)Ba^(141)+_(36)Kr^(92)+3_(0)n^(1)+E . Calculate: The energy released when 1 g of ._(92)U^(235) undergoes complete fission in N if m=[N] then find (m-2)/(5) . [N] greatest integer Given ._(92)U^(235)=235.1175"amu (atom)" , ._(56)Ba^(141)=140.9577 "amu (atom)" , ._(36)r^(92)=91.9263 "amu(atom)" , ._(0)n^(1)=1.00898 "amu", 1 "amu"=931 MeV//C^(2)

Find the amount of energy produced in joules due to fission of 1 gram of uranium assuming that 0.1 percent of mass is transformed into energy. Take 1amu= 1.66xx10^(-27)kg=931.5MeV Mass of uranium =235amu. Avogadro number = 6.02xx10^(23)

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