In the fusion reaction `._1^2H+_1^2Hrarr_2^3He+_0^1n`, the masses of deuteron, helium and neutron expressed in amu are `2.015, 3.017 and 1.009` respectively. If `1 kg` of deuterium undergoes complete fusion, find the amount of total energy released. 1 amu `=931.5 MeV//c^2`.

Explanation

To solve the problem step by step, we will follow the outlined process to find the total energy released when 1 kg of deuterium undergoes complete fusion.

### Step 1: Calculate the Mass Defect
The fusion reaction is given as:
\[ _1^2H + _1^2H \rightarrow _2^3He + _0^1n \]

We need to calculate the mass defect (\(\Delta m\)) for this reaction. The mass defect is calculated as:
\[
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