How may `alpha-` and `beta-` particles will be emitted when `._(90)Th^(232)` changes into `._(82)Pb^(208)`?

Explanation

To determine how many alpha (α) and beta (β) particles are emitted when \( _{90}^{232}\text{Th} \) changes into \( _{82}^{208}\text{Pb} \), we can follow these steps:

### Step 1: Identify the initial and final nuclei
- The initial nucleus is Thorium-232, denoted as \( _{90}^{232}\text{Th} \).
- The final nucleus is Lead-208, denoted as \( _{82}^{208}\text{Pb} \).

### Step 2: Calculate the change in mass number
- The mass number of Thorium is 232 and that of Lead is 208.
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