Determine the amount of `""_(84)Po^(210)` (polonium ) necessary to provide a source of `alpha ` -particles of 5 millicurice strength , if life of polonium is 138 days (given ,1 curie `=3.7xx10^(10)` disintegrations /s )

Explanation

To determine the amount of Polonium-210 necessary to provide a source of alpha particles of 5 millicurie strength, we can follow these steps:

### Step 1: Convert the activity from millicuries to disintegrations per second
Given that 1 curie (Ci) = \(3.7 \times 10^{10}\) disintegrations/s, we can convert 5 millicuries to disintegrations per second.

\[ R = 5 \text{ mCi} = 5 \times 10^{-3} \text{ Ci} = 5 \times 10^{-3} \times 3.7 \times 10^{10} \text{ disintegrations/s} \]
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