Home
Class 12
PHYSICS
In a fission reaction .92^236 U rarr ^11...

In a fission reaction `._92^236 U rarr ^117 X + ^117Y + n + n`, the binding energy per nucleon of `X` and `Y` is `8.5 MeV` whereas of `.^236 U` is `7.6 MeV`. The total energy liberated will be about.

A

200 keV

B

2 MeV

C

200 MeV

D

2000 MeV

Text Solution

AI Generated Solution

To solve the problem, we need to calculate the total energy liberated during the fission reaction of Uranium-236 into nuclei X and Y, along with the release of neutrons. The energy released can be calculated using the binding energy per nucleon of the reactants and products. ### Step-by-Step Solution: 1. **Identify the Given Data:** - Binding energy per nucleon of Uranium-236 (\( ^{236}U \)): \( 7.6 \, \text{MeV} \) - Binding energy per nucleon of nuclei \( X \) and \( Y \): \( 8.5 \, \text{MeV} \) - Mass number of Uranium-236: \( 236 \) ...
Promotional Banner

Topper's Solved these Questions

  • NUCLEI

    DC PANDEY ENGLISH|Exercise CHECK POINT 13.3|15 Videos
  • NUCLEI

    DC PANDEY ENGLISH|Exercise CHAPTER EXERCISES|78 Videos
  • NUCLEI

    DC PANDEY ENGLISH|Exercise checkpoint 13.1|10 Videos
  • MODERN PHYSICS - 2

    DC PANDEY ENGLISH|Exercise Level 2 Subjective|10 Videos
  • RAY OPTICS

    DC PANDEY ENGLISH|Exercise Medical entrance gallary|76 Videos

Similar Questions

Explore conceptually related problems

Consider the following nuclear reaction, X^200rarrA^110+B^90+En ergy If the binding energy per nucleon for X, A and B are 7.4 MeV , 8.2 MeV and 8.2 MeV respectively, the energy released will be

Consider the following nuclear reaction, X^200rarrA^110+B^90+En ergy If the binding energy per nucleon for X, A and B are 7.4 MeV, 8.2 MeV and 8.2 MeV respectively, the energy released will be

Consider the nuclear reaction X^(200)toA^(110)+B^(80)+Q . If the binding energy per nucleon for X, A and B are 7.4 MeV, 8.2 MeV and 8.1 MeV respectively, then the energy released in the reaction:

In the reaction ._1^2 H + ._1^3 H rarr ._2^4 He + ._0^1 n , if the binding energies of ._1^2 H, ._1^3 H and ._2^4 He are respectively a,b and c (in MeV), then the energy (in MeV) released in this reaction is.

In the reaction ._1^2 H + ._1^3 H rarr ._2^4 He + ._0^1 n , if the binding energies of ._1^2 H, ._1^3 H and ._2^4 He are respectively a,b and c (in MeV), then the energy (in MeV) released in this reaction is.

A heavy nucleus X of mass number 240 and binding energy per nucleon 7.6 MeV is split into two fragments Y and Z of mass numbers 110 and 130 . The binding energy of nucleons in Y and Z is 8.5MeV per nucleon. Calculate the energy Q released per fission in MeV.

The energy of the reaction Li^(7)+prarr2He^(4) is ( the binding energy per nucleon in Li^(7) and He^(4) nuclei are 5.60 and 7.60 MeV respectively.)

Consider the nuclear fission Ne^(20) rarr 2He + C^(12) .The binding energy per nucleon are 8.03 MeV, 7.07 MeV and 7.86 MeV respectively. identify the correct statement

The mass defect for the nucleus of helium is 0.0303 a.m.u. What is the binding energy per nucleon for helium in MeV ?

A heavy nuleus having mass number 200 gets disintegrated into two small fragmnets of mass numbers 80 and 120 . If binding energy per nulceon for parent atom is 6.5 MeV and for daughter nuceli is 7 MeV and 8 MeV , respectivley , then the energy released in the decay will be.