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A radioactive element ""(90)X^(238) deca...

A radioactive element `""_(90)X^(238)` decay into `""_(83)^(222)` , then the number of `beta^-` -particles emitted are

A

One alpha and one electron

B

Two deuterons and one positron

C

One alpha and one proton

D

One proton and four neutrons

Text Solution

Verified by Experts

The correct Answer is:
A
`""_(92)X^(235)overset(alpha)to_(90)X^(231)overset(beta^(-))to_(91)Y^(231)`
Therefore, one alpha and one electron are emitted.
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