The radioactivity of an element becomes ...

The radioactivity of an element becomes `(1)/(64)`th of its original value in 60 seconds. Then the half life period of element is

A

5 s

B

10 s

C

30 s

D

20 s

Text Solution

Verified by Experts

The correct Answer is:

B

We have , `1/64=((1)/(2))^(n)n=6`
6 half-lives are equal to 60 s.
`therefore` 1 half-life = 10 s

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