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What is the binding energy per nucleon i...

What is the binding energy per nucleon in `""_2He^4` ?
Given , Mass of `""_2He^4=4.002604` amu
Mass of proton= 1.007825 amu
mass of neutron =1.008665 amu

A

5.26 MeV

B

6.2 MeV

C

4.65 MeV

D

7.68 MeV

Text Solution

Verified by Experts

The correct Answer is:
D
Binding energy per nucleon
`([{m_(p)Z+m_(n)(A-Z)}-M]xx931)/("Mass number A")`
`=((6xx1.0078+6xx1.0087-12)/(12))xx931.4`
= 7.68 MeV
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