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Two identical blocks A and B of equal ma...

Two identical blocks A and B of equal masses are placed on rough inclined plane as shown in the figure. Initially the block A is `sqrt(2) `m behind the block B. Coefficient of kinetic friction for the blocks A and B are 0.2 and 0.3 respectively `(g = 10 m//s^(2))`. By the time the two blocks come on the same line on the inclined plane if they are released simultaneously, the distance moved by B is `beta m` Find the value of `beta`

A

`Yto2Z`

B

`WtoX+Y`

C

`Wto2Y`

D

`XtoY+Z`

Text Solution

Verified by Experts

The correct Answer is:
C
Energy is released in a process when total binding energy (BE) of the nucleus is increased or we can say when total BE of products is more than the reactants. By calculation we can see that only in case of option (c ), this happens.
Given, `W to 2Y`
BE of reactants `=120xx7.5=900 MeV` and BE of products `=90xx8+60xx8.5=1230MeV` i.e., BE of products `gt` BE of reactants.
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