The gravitational force between a H-atom and another particle of mass m will be given by Newton's law: `F=G (M.m)/(r^(2)`, where r is in km and

Options

A. `M=m_("proton")+m_("electron")`
B. `M=m_("proton")+m_("electron")-(B)/(c^(2))(B=13.6eV)`
C. M is not relate to the mass of the hydrogen atom
D. `M=m_("proton")+m_("electron")-(|V|)/(c^(2))(|V|` = magnitude of the potential energy of electron in the H-atom)

Answer

B

Explanation

Given, `F(GMm)/(r^(2)),` where
M = effective mass of hydrogen atom = mass of electron + mass of proton `-(B^(2)//c^(2))` where, B is BE hydrogen atom = 13.6 eV