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A rodiactive nucleus is being produced a...

A rodiactive nucleus is being produced at a constant rate `alpha` per second Its decay constant is `lambda` If `N_(0)` are the number of nuclie at tieme t=O then, maximum number of nuclei possible are

A

`(alpha)/(lamda)`

B

`N_(0)+(alpha)/(lamda)`

C

`N_(0)`

D

`(alpha)/(lamda)+N_(0)`

Text Solution

Verified by Experts

The correct Answer is:
A

Maximum number of unclei will be present when rate of decay= rate of formation
`lamdaN=alpha`
Maximum number of nuclei, `N = alpha//lamda`
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