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Two spherical nuclei have mass number 21...

Two spherical nuclei have mass number 216 and 64 with their radii `R_(1) and R_(2)` respectively. The ratio, `(R_(1))/(R_(2))` is equal to

A

`3:2`

B

`1:3`

C

`1:2`

D

`2:3`

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The correct Answer is:
To solve the problem of finding the ratio of the radii of two spherical nuclei with mass numbers 216 and 64, we can follow these steps: ### Step 1: Understand the formula for the radius of a nucleus The radius \( R \) of a nucleus can be expressed in terms of its mass number \( A \) using the formula: \[ R = R_0 A^{1/3} \] where \( R_0 \) is a constant approximately equal to \( 1.2 \times 10^{-15} \) meters. ### Step 2: Write the expressions for the radii of the two nuclei Let \( R_1 \) be the radius of the nucleus with mass number \( A_1 = 216 \) and \( R_2 \) be the radius of the nucleus with mass number \( A_2 = 64 \). We can write: \[ R_1 = R_0 (216)^{1/3} \] \[ R_2 = R_0 (64)^{1/3} \] ### Step 3: Find the ratio of the radii To find the ratio \( \frac{R_1}{R_2} \), we can substitute the expressions for \( R_1 \) and \( R_2 \): \[ \frac{R_1}{R_2} = \frac{R_0 (216)^{1/3}}{R_0 (64)^{1/3}} \] The \( R_0 \) cancels out: \[ \frac{R_1}{R_2} = \frac{(216)^{1/3}}{(64)^{1/3}} = \left(\frac{216}{64}\right)^{1/3} \] ### Step 4: Simplify the fraction Now, we simplify \( \frac{216}{64} \): \[ \frac{216}{64} = \frac{27}{8} = \left(\frac{3}{2}\right)^3 \] Thus, \[ \frac{R_1}{R_2} = \left(\frac{3}{2}\right)^{1} = \frac{3}{2} \] ### Step 5: State the final answer Therefore, the ratio of the radii \( \frac{R_1}{R_2} \) is: \[ \frac{R_1}{R_2} = \frac{3}{2} \] ### Final Answer The ratio \( \frac{R_1}{R_2} \) is \( \frac{3}{2} \). ---

To solve the problem of finding the ratio of the radii of two spherical nuclei with mass numbers 216 and 64, we can follow these steps: ### Step 1: Understand the formula for the radius of a nucleus The radius \( R \) of a nucleus can be expressed in terms of its mass number \( A \) using the formula: \[ R = R_0 A^{1/3} \] where \( R_0 \) is a constant approximately equal to \( 1.2 \times 10^{-15} \) meters. ...
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