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A radioactive element X disintegrates su...

A radioactive element X disintegrates successively
`Xoverset(beta^(-))toX_(1)overset(alpha)toX_(2)overset(beta_(-))toX_(3)overset(alpha)toX_(4)`
If atomic number and atomic mass number of X are respectively, 72 and 180, then what are the corresponding values for `X_(4)` ?

A

69172

B

69176

C

71176

D

`70.172`

Text Solution

Verified by Experts

The correct Answer is:
D
(d) the disintegration can be shown as below .
`""_(72)X^(180) (-2overset(-)beta )/(-2alpha )X_(4) `
Loss in atomic number `=72+2-4=70`
Loss in mass number `=180-8=172`
SO , final nucleus is `""_(70)X_(4)^(172).`
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