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The energy released by the fission of on...

The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to prodice 6.4W power is

A

`2xx10^(11)`

B

`10^(11)`

C

`10^(10)`

D

`2xx10^(10)`

Text Solution

Verified by Experts

The correct Answer is:
A
(a) Let there is n number of fission per second produces a power of 6.4 W, then
`nxx200x10^(6) xx16x10^(-19) Js^(-1) =6.4Js^(-1)`
`therefore n=(6.4)/( 200xx10^(-13) xx1.6)=(4)/(2xx10^(-11))=2xx10^(11)`
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