In the given reaction
`._z X^A rarr ._(z+1)Y^A rarr ._(z-1) K^(A - 4) rarr ._(z-1) K^(A - 4)`
Radioactive radiations are emitted in the sequence.

Options

A. `alpha,betagamma`
B. `gamma,alpha,beta`
C. `beta,alpha,gamma`
D. `lamda,beta,alpha`

Answer

C

Explanation

Suppose a given nucleus is `""_(Z)X^(A)`.
In `alpha-"decay"`, the mass number of the product nucleus I sfour less than that of decaying nucleus, while the atomic number decreases by two.
`""_(Z)X^(A)overset(alpha-"decay")to""_(Z-2)X^(A-4)""_(2)He^(4)(alpha)`
In `beta-"decay`, the mass number of product nucleus remains same but atomic number increases or decreases by one.
`""_(Z)^(A)Xoverset(beta-"decay")to""_(Z)^(A)+""_(1)Y+_(-1)^(0)e+v`
or `""_(Z)^(A)Xoverset(beta-"decay")to""_(Z)^(A)+""_(1)Y+_(+1)^(0)e+v`
Gamma decay is the phenomenon of emission of gamma rays photon from a radioactive nucleus.
`""_(Z)X^(A)to""_(Z)X^(A)+y`
Hence, the given reaction will have sequence as follows
`""_(Z)X^(A)overset(beta-"emission")to""_(Z+1)Yoverset(alpha-"emission")to`
`""_(Z-1)K^(A-Y)overset(y-"emission")to""(Z-1)K^(A-y)`