Bichromatic light is used in YDSE having wavelengths `lambda_(1)=400nm` and `lambda_(2)=700nm` Find minimum order of `lambda_(1)` which overlaps with `lambda_(2)`

Explanation

To solve the problem of finding the minimum order of wavelength \( \lambda_1 = 400 \, \text{nm} \) that overlaps with wavelength \( \lambda_2 = 700 \, \text{nm} \) in Young's Double Slit Experiment (YDSE), we can follow these steps:

### Step 1: Understanding the Condition for Overlap
In YDSE, the condition for the bright fringes to overlap is given by the formula:
\[ \frac{n_1}{n_2} = \frac{\lambda_2}{\lambda_1} \]
where \( n_1 \) is the order of the fringe for \( \lambda_1 \) and \( n_2 \) is the order of the fringe for \( \lambda_2 \).
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