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Monochromatic green light of wavelength ...

Monochromatic green light of wavelength `5 xx 10^(-7) m` illuminates a pair of slits 1 mm apart. The separation of bright lines on the interference pattern formed on a screen 2 m away is

A

`0.25` mm

B

`0.1 mm`

C

`1.0 mm`

D

`0.01mm`

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The correct Answer is:
To solve the problem of finding the separation of bright lines (fringe width) in an interference pattern created by two slits illuminated by monochromatic green light, we can follow these steps: ### Step 1: Identify the given data We have the following information: - Wavelength of light, \( \lambda = 5 \times 10^{-7} \, \text{m} \) - Distance between the slits, \( d = 1 \, \text{mm} = 1 \times 10^{-3} \, \text{m} \) - Distance from the slits to the screen, \( D = 2 \, \text{m} \) ### Step 2: Use the formula for fringe width The formula for fringe width (the separation between two consecutive bright lines) in a double-slit interference pattern is given by: \[ \beta = \frac{D \lambda}{d} \] where: - \( \beta \) is the fringe width, - \( D \) is the distance from the slits to the screen, - \( \lambda \) is the wavelength of the light, - \( d \) is the distance between the slits. ### Step 3: Substitute the values into the formula Now we will substitute the values into the formula: \[ \beta = \frac{(2 \, \text{m}) \cdot (5 \times 10^{-7} \, \text{m})}{1 \times 10^{-3} \, \text{m}} \] ### Step 4: Calculate the fringe width Calculating the above expression: \[ \beta = \frac{2 \cdot 5 \times 10^{-7}}{1 \times 10^{-3}} \] \[ = \frac{10 \times 10^{-7}}{1 \times 10^{-3}} \] \[ = 10 \times 10^{-7 + 3} = 10 \times 10^{-4} \, \text{m} = 1 \times 10^{-3} \, \text{m} = 1 \, \text{mm} \] ### Step 5: Conclusion The separation of bright lines (fringe width) on the interference pattern is \( 1 \, \text{mm} \).

To solve the problem of finding the separation of bright lines (fringe width) in an interference pattern created by two slits illuminated by monochromatic green light, we can follow these steps: ### Step 1: Identify the given data We have the following information: - Wavelength of light, \( \lambda = 5 \times 10^{-7} \, \text{m} \) - Distance between the slits, \( d = 1 \, \text{mm} = 1 \times 10^{-3} \, \text{m} \) - Distance from the slits to the screen, \( D = 2 \, \text{m} \) ...
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DC PANDEY ENGLISH-WAVE OPTICS-Check point
  1. In a Young's double slit experiment, the fringe width will remain same...

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  2. Interference was observed in interference chamber when air was present...

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  3. Monochromatic green light of wavelength 5 xx 10^(-7) m illuminates a ...

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  4. In double slits experiment, for light of which colour the fringe width...

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  5. The Young's double slit experiment is performed with blue light and gr...

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  6. In Young's double slit experiment, green light (lambda=5461Å) is used ...

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  7. In Young's doble-slit experiment, if the monochromatic source of light...

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  8. In the Young's double slit experiment, the interference pattern is fou...

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  9. What happens to the fringe pattern if in the path of one of the slits ...

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  10. In a double-slit experiment, instead of taking slits of equal width, o...

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  11. In a Young's double-slit expriment using identical slits, the intensit...

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  12. When a transparent parallel plate of uniform thickness t and refractiv...

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  13. A thin mica sheet of thickness 2xx10^-6m and refractive index (mu=1.5)...

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  14. In Young's double slit experiment, the aperture screen distance is 2m....

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  15. Interference fringes were produced in Young's double-slit experiment u...

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  16. What is the minimum thickness of a thin film (mu=1.2) that results in ...

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  17. The phenomenon of diffraction of light was discovered by-

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  18. In Young's double slit experiment the type of diffractive is

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  19. The bending of light about corners of an obstacle is called

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  20. To observe diffraction, the size of the obstacle

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