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A long solonoid carrying a current produ...

A long solonoid carrying a current produces a magnetic field along its axis. If the current is doubled and the number of turns per cm is halved, the new value of the magnetic field is

A

Wire should be multiple of 5d

B

Wire should be multiple of `d//3`

C

Wire is independent of d

D

Can 't say

Text Solution

Verified by Experts

The correct Answer is:
C

The cross sectional area of the space to be filled is fiexd withlist that of the wire varies as `d^(2)` Thus `nprop d^(-2)` . The resistacne of one turn is inversely proportional to the cross sectional area of the wire i.e varies as `d^(-2)` and hence the resistance per unit length of the solenoid is `Rpropnd^(-2)propd^(-4)` The flux density `Bis prop nI` and therefore the required current `Ipropn^(-1)propd^(2)` The heat dissipated per unit length is `RI^(2)`, Which `propd^(-4)(d^(2)^(2))` i.e independent of chosen so far as the heatin effect is concerned.
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Knowledge Check

  • A circular coil carrying a current I has radius R and number of turns N. If all the three, i.e., the current I, radius R and number of turns N are doubled, then, magnetic, field at its centre becomes:

    A
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    B
    Half
    C
    Four times
    D
    One-fourth
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