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White light is used to illuminate the tw...

White light is used to illuminate the two slits in a Young's double slit experiment. The separation between the slits is b and the screen is at a distance `d (gt gtb)` from the slits At a point on the screen directly in front of one of the slits, certain wavelengths are missing some of these missing wavelengths are

A

`lambda=b^(2)=b^(2)//d`

B

`lambda=b^(2)=2b^(2)//d`

C

`lambda=b^(2)=b^(2)//3d`

D

`lambda=2b^(2)=b^(2)//3d`

Text Solution

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The correct Answer is:
To solve the problem of determining the missing wavelengths in a Young's double slit experiment with white light, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Setup**: - We have two slits separated by a distance \( b \). - A screen is placed at a distance \( d \) from the slits. - We are looking for the wavelengths that are missing at a point on the screen directly in front of one of the slits. 2. **Condition for Dark Fringes**: - The condition for dark fringes in a double-slit experiment is given by the formula: \[ y = \frac{(2n - 1) \lambda d}{b} \] - Here, \( y \) is the distance from the central maximum to the dark fringe, \( n \) is the order of the dark fringe, \( \lambda \) is the wavelength of light, \( d \) is the distance from the slits to the screen, and \( b \) is the separation between the slits. 3. **Finding the Position of Dark Fringes**: - At the point directly in front of one of the slits, the distance \( y \) can be set to \( \frac{b}{2} \) (half the distance between the slits). - Substituting \( y = \frac{b}{2} \) into the dark fringe formula gives: \[ \frac{b}{2} = \frac{(2n - 1) \lambda d}{b} \] 4. **Rearranging the Equation**: - Cross-multiplying gives: \[ b^2 = (2n - 1) \lambda d \] - Rearranging for \( \lambda \) gives: \[ \lambda = \frac{b^2}{(2n - 1) d} \] 5. **Calculating Missing Wavelengths**: - For different values of \( n \): - For \( n = 1 \): \[ \lambda_1 = \frac{b^2}{1 \cdot d} = \frac{b^2}{d} \] - For \( n = 2 \): \[ \lambda_2 = \frac{b^2}{3d} \] - For \( n = 3 \): \[ \lambda_3 = \frac{b^2}{5d} \] 6. **Identifying Missing Wavelengths**: - The wavelengths that are missing at the point directly in front of one of the slits are: - \( \frac{b^2}{d} \) - \( \frac{b^2}{3d} \) - \( \frac{b^2}{5d} \) 7. **Conclusion**: - The missing wavelengths correspond to the values derived above. Thus, the correct answers for the missing wavelengths are \( \frac{b^2}{d} \) and \( \frac{b^2}{3d} \).
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