A solid has a ccp arrangement of `O^(2-)` ions. All of the tetrahedral voids are occupied by `Na^+` ions. Find molecular formula.

In a cubic lattice, the close packed structure of mixed oxides of the lattice is made up of oxide ion, one eighth of the tetrahedral voids are occupied by divalent ions (X^(2+)) while one half of the octahedral voids are occupied by trivalent ions (Y^(3+)) . What is the formula of the oxide?

In a cubic close packed structure of mixed oxides, the lattice is composed of oxide.ions, one eighth of tetrahedral voids are occupied by divalent cations while one hálf of octahedral voids are occupied by trivalent cations. What is the formula of the oxide

In spinel structure, O^(2-) ions are cubic-close packed, where 1/8th of the tetrahedral holes are occupied by A^(2+) cations and 1/2 of the octahedral holes are occupied by cations B^(3+) . The general formula of this compound is

In a compound, atom A form ccp arrangement, atom B present in 12.5% of the tetrahedral voids and atom C present in 25% of the octahedral voids and rational formula is expressed as A_(x)B_(y)C_(z) then value of (x+y+z) is:

A compound of A, B and C has cubic close packed arrangement of A, B occupy one half of octahedral voids and C occupy 1//4^(th) of tetrahedral voids. The simplest formula of the compound is

In a compound, oxide ions have a ccp arrangment. Cations A are present in 1/8 th of tetrahedral holes and cations B occupy 1/2 of octahedral holes. The simpliest formula of the compound is