Calculate the mole fraction of benzene in solution containing `30%` by mass in `CCl_4`

Explanation

Mass of solution =100g
Mass of benzene = 30g
Number of moles of benzene = (Mass)/(Molar mass) = 30/78 = 0.385
Mass of `CCl_4` = 100-30 = 70g
Number of moles of `CCl_4`= (Mass)/(Molar mass) = 70/154 = 0.458
`therefore` Mole fraction of benzene =(Number of moles of `C_6H_6`)/(Total number of moles)= `0.385/(0.385+0.455) = 0.458`