A mixture contain 3.2g methanol (molecular mass =32 u) and 4.6 g ethanol (molecular mass =46 u) Find the mole fraction of each component.

Explanation

Number of moles of methanol `n_1 = 3.2/32=0.1`
Number of moles of ethanol `n_2 = 4.6/46=0.1`
Mole fraction ethanol`=0.1/(0.1+0.1)= 0.1/0.2= 0.5 because x_("Methanol") = 1- 0.5= 0.5`