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Calculate the emf of the cell in which t...

Calculate the emf of the cell in which the following reaction takes place:
`Ni(s)+ 2Ag^+(0.002M) to Ni^2(0.160 M)+2Ag(s)`. Given that `E_(cell)^0=1.05V`

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`E_(cell)=E_(cell)^0-0.059/nlog[Ni^(2+)]/[Ag^+]^2`
`=1.05-0.059/2log0.160/(0.002)^2=1.05-0.059/2log(4xx10^4)`
`1.05-0.0295xx4.6021=1.05-0.135=0.914V`
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