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lamdam^0for NaCl,HCL and NaAc are 126.4,...

`lamda_m^0`for NaCl,HCL and NaAc are 126.4,425.9and`91.0Scm^2mol^(-1)`respectively. Calculate`^^_m^0`for Hac.

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`^^_m^0(HA_C)=lamda_m^0(NaAc)+lamda_m^0(HCL)-lamda_m^0(NaCl)`
`=91+425.9-126.4=390.5Scm^2mol^(-1)`
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A N EXCEL PUBLICATION-ELECTROCHEMISTRY-QUESTION BANK
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