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How will you convert: Cl-(CH2)4-Cl into ...

How will you convert: `Cl-(CH_2)_4-Cl` into hexane-1, 6-diamine?

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`Cl-(CH_2)_4-Cl` is treated with excess KCN and the dicyanide formed is reduced with `LiAlH_4`
`Cl-(CH_2)-Cloverset(2KCN)toNC-(CH_2)_4-CNoverset(LiAlH_4)toH_2N-(CH_2)_6-NH_2`
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A N EXCEL PUBLICATION-AMINES-QUESTION BANK
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