A steel wire of length 1.5m and diameter 0.25cm is loaded with a force of 98N The increase in length of the wire is `1.5xx10^-4m`.Calculate the tensile stress and the fractional change in length of the wire.

Explanation

L=1.5m, r=d/2 =`0.125xx10^-2 m, F=98N, deltaL=1.5xx10^-4m` Stress `=F/A = F/pi r^2 =98//3.14xx(0.125xx10^-2)^2=1.99xx10^7Nm^-2 ` Fractional change in length, `deltaL//L= 1.5xx10^-4//1.5 =10^-4`