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Let x be the length of one of the equal ...

Let x be the length of one of the equal sides of an isosceles triangle, and let `theta` be the angle between them. If x is increasing at the rate (1/12) m/h/ and `theta` is increasing at the rate of `pi//180` radians/h then the rate in `m^(2)//h` at which the area of the triangle whe x = 12m and `theta = pi //4`

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The correct Answer is:
`sqrt2 (pi/5+1/2)`
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