Home
Class 11
CHEMISTRY
If 32 g of O(2) contain 6 022 xx 10^23 ...

If 32 g of `O_(2)` contain `6 022 xx 10^23` molecules at NTP then 32 g of S, under same conditions, will contain,

A

`6.022 xx 10^(23)` S

B

`3.011 xx 10^(23)` S

C

`12.044 xx 10^(23) S`

D

`1 xx 10^(23) S`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

32 g of a gas contains 6.022 xx 10^(23) molecules. Its vapour density is 8 , 10, 12, 16

6.022 xx 10^(22) molecules of N_(2) at NTP will occupy a volume of

Find the mass of. 6.02xx10^23 molecules of CO_2

One gram mole of a substance contains 6.022xx10^23 molecules. Find out the number of molecules in 2.8 g of nitrogen.

Calculate the weight of 6.022 xx 10^(23) molecules of CaCO_(3)

One gram mole of a substance contains 6.022xx10^23 molecules. 24 g of carbon is treated with 72 g of oxygen to form CO_2 . Find the number of molecules of CO_2 formed in this situation.

One gram mole of a substance contains 6.022xx10^23 molecules. 24 g of carbon is treated with 72 g of oxygen to form CO_2 . Identify the limiting reagent.

Pick out the correct statements from the following. Also correct the incorrect statements. a) The number of molecules present in 1 mol hydrogen and 1 mol oxygen are same. b) 1 mole chlorine contain 4 xx 6.022 xx10^23 chlorine molecules. c) The mass of 1/2 mol nitrogengas is 14g. d) 0.5 mol water has the mass of 9g. There are 6.022 xx 10^23 H_2 O molecules in it. (Atomic mass H= 1.0= 16, Cl 35.5, N = 14).