Home
Class 11
CHEMISTRY
Naturally occurring boron consists of tw...

Naturally occurring boron consists of two isotopes whose atomic weights are 10.01 and 11.01. The atomic weight of natural boron is 10.81. Calculate the percentage of each isotope in natural boron.

Text Solution

Verified by Experts

NA
Promotional Banner

Similar Questions

Explore conceptually related problems

Naturally occuring boron has two isotopes of masses 10 amu and 11 amu. Calculate the percentage of each isotope if the average atomic mass of boron is 10.2 .

Boron has two isotopes ""_(5)^(10)B and ""_(5)^(11)B . If the atomic weight of boron is 10.81, the ratio of ""_(5)^(10)B and ""(5)^(11)B in nature is

Calculate the weight of 12.044 xx 10^(23) atoms of carbon.