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0.13 g of Cu, when treated with AgNO3 so...

0.13 g of Cu, when treated with `AgNO_3` solution, displaced `0.433` g of `Ag`.
`0.13` g of `AI`, when treated with `CuSO_4` solution displaced `0.47 ` g of `Cu`. 1.17 g of AI displaces `0.13` g of hydrogen from an acid. Find the equivalent weight of Ag if equivalent weights of Cu and Al are not known.

Text Solution

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`underset(0.13g)(Cu)+ AgNO_3 to underset(0.433g)(Ag) " "...(1)`
`underset(0.13g)(AI)+ CuSO_4 to underset(0.47g)(Cu)" "...(2)`
`underset(1.17g)(AI) + "Acid" to underset(0.13g)(H_2)" "...(3)`
For Eqn. (3) : eq. of Al = eq. of hydrogen
`therefore (1.17)/("eq. w. of AI")= (0.13)/(1),` eq. wt. of Al is 9.
For Eqn. (2) : eq. of Al = eq. of Cu
`therefore (0.13)/(9) = (0.47)/("eq. wt. of Cu"),` eq. wt. of Cu= 32.5.
For Eqn. (1) : eq. of Cu = eq. of Ag
`therefore (0.13)/( 32.5) = (0.433)/("eq. wt. of Ag")`
eq. wt. of Ag= 108.25.
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