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The equivalent weight of MnSO4 is half i...

The equivalent weight of `MnSO_4` is half its molecular weight when it is com1erted to (a) `Mn_(2) O_(3)` (b) `MnO_(2)` (c ) `MnO_(4)^(-)` (d) `MnO_(4)^(2-)`. Indicate the correct answer.

Text Solution

Verified by Experts

In (b),
`underset(+2)( MnSO_(4) )to underset(+4) ( MnO_(2) )`
Change in ON of Mn per mole of `MnSO_4 =2`
`therefore` eq. wt. of `MnSO_4 = ("Mol. wt.")/(2)`
Hence the answer is (b).
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