धारा `i = 3 + 4 sin (omega t + pi//3)` का वर्ग माध्यमूल मान होगा-

Options

A. 5A
B. `sqrt(17)` A
C. `(5)/(sqrt(2))`A
D. `(7)/(sqrt(2))`A

Answer

B

Explanation

`i = 3 + 4 sin (omega t + pi//3)`
`i^(2) = 9 + 16 sin^(2)(pi t + pi//3) + 24 sin (omega t + pi//3)`
` lt i^(2) gt`
`= 9 + 16 [1//2] + 24 [0]`
`= 9 + 16 ((1)/(2))`
= 17
`therefore` r.m.s. value = `sqrt(17)`