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Constract the composition table/multipli...

Constract the composition table/multiplication table for the binary operation * defined on {0,1,2,3,4}by `a**b =axxb ("mod" =5)`. Find the identity element if any. Also find the inverse elements of 2 and 4.

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`A ={0,1,2,3,4}`
`a**b =axx b "mod" 5`

As 3rd row is identical to the first row we have 1 is the identity clearly `2^(-1) =3 "and" 4^(-1) =4.`
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