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(Allocation Problem.)A farmer has 5 acre...

(Allocation Problem.)A farmer has 5 acres of land on which he wishes to grow two crops X and Y. He has to use 4 cart loads and 2cart loads of manure per acre for crops X and Y respectively. But not more than 18 cart loads of manure is available. Other expenses are ₹200 and ₹500 per acre for the crops X and Y respectively . He estimates profit from crops X and Y at the rates ₹1000 and ₹800 per acre respectively. Formulate the LPP as to how much land he should allocate to each crop for maximum profit.

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MBD PUBLICATION-LINEAR PROGRAMMING-QUESTION BANK
  1. A factory uses three different respurce for the manufacture of two dif...

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  2. A man plans to start a poultry farm by investing at most ₹ 3000. He ca...

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  3. (Allocation Problem.)A farmer has 5 acres of land on which he wishes t...

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  4. Special purpose coins each weighing 10gms are to be manufactured using...

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  5. A company produces three types of cloth A,B and C. Three kinds of wool...

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  6. MaximizeZ =5x1+6x2 "Subject to" : 2x1 +3x2 le 6 x1,x2 ge 0

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  7. Minimize:Z=6x1+7x2 "Subject to":x1+2x2 ge 4 x1,x2 ge 0

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  8. Maximize :Z=20x1+40x2 "Subject to" :x1+x2 le 1 x1,x2 ge 0.

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  9. Solve the following LPP graphically. Minimize z=30x1+45x2 subject to 2...

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  10. Optimize :Z=5x1+25x2 "Subject to":-0.5x1+x2 le 2 -x1+5x2 ge 5 x1,x2 g...

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  11. Maximize:Z=14x1+4x2 "Subject to":x1+12x2 le 65 7x1 -2x2 le 25 2x1+3x2 ...

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  12. Maximize:Z=10x1+12x2+8x3 "Subject to": x1+2x2 le 30 5x1 -7x3 ge 12 x1+...

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  13. Minimize:Z=20x1+10x2 "Subject to": x1+2x2 le 40 3x1 -x2 ge 30 4x1+3x2 ...

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  14. MaximizeZ =4x1+3x2 "Subject to" : x1 +x2 le 50 x1+2x2 le 80 2x1+x2 ge ...

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  15. Maximize :Z=20x1+40x2 "Subject to" :x1+x2 le 1 x1,x2 ge 0.

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  16. Minimize:Z=6x1+7x2 "Subject to":x1+2x2 ge 4 x1,x2 ge 0

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  17. Maximize :Z =1500x +2000y "Subject to" :x+y lt 20 x+2y lt 24 x,y ge ...

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  18. Maximize :Z= 15x +10y "Subject to" : 2x +3y le 600 2x+y le 480 x,y ge ...

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  19. Maximize :Z =20x +30y "Subject to": x+2y le 10 x+y le 6 x le 4 x,y ge...

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  20. Maximize : Z=2x +4y "Subject to" 3x +2y le 10 2x+5y le 15 5x +6y le 21...

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