Find the inverse of the following :
`[[i,-i],[i,i]`

Explanation

`[[i,-i],[i,i]`
`therefore absA=i^2_i^2=-1-1=-2 ne 0`
`therefore C_11=i, C_12=-i, C_21=i, C_22=i`
Let B=`[[C_11,C_12],[C_11,C_22]]=[[i,-i],[i,i]]`
`therefore adjA=B.=[[i,i],[-i,i]`
`therefore A^-1 =(adjA)/(absA)=([[i,i],[-i,i]])/-2`
=`[[i/-2,i/-2],[i/2,-i/2]]`