If you throw a pair of dice n times, find the probability of getting at least one doublet.[When you get identical members you call it a doublet. You can get a double in six ways: (1,1),(2,2),(3,3),(4,4),(5,5) and (6,6) , thus the probability of getting a doublet is `6/36=1/6`, so that the probability of not getting a doublet in one throw is `5/6]`.

Explanation

A pair od dice is thrown n times. We get the doublet as (1,1),(2,2),(3,3),(4,4),(5,5),(6,6).
`therefore` Probability of getting a doublet in one throw `=6/36=1/6`
`therefore` Probability of not getting a doublet `=1-1/6=5/6`
If a pair of dice is known n-times, the probability of not getting a doublet `=(5/6)^n`
`therefore` Probability of getting atleast one doublet `=1-(5/6)^n`