Find the velocity and acceleration at the end of 2 seconds of the particle moving according to the following rules. `s = 3/2t + 1`

Explanation

`s = 3/2t + 1 `
ds/dt = 6/(2t + 1)^2 (d^2s)/dt^2 = 24/ (2t + 1)^3`
Now `ds/dt](t = 2) = 6/25`
(d^2s)/dt^2](t = 2) = 24/125`
`therefore` Velocity is - 6/25 units/sec and acceleration is 24/125 `units/sec^2` .