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Intergrate the following: intsin4x cos...

Intergrate the following:
`intsin4x cos3xdx`

Text Solution

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`intsin4x cos3xdx`
=`1/2 int2sin4x .cos3xdx`
=`1/2int(sin7x+sinx)dx`
=`1/2{-(cos7x)/7-cosx}+C`
=-1/14cos7x-1/2 cosx+C
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