`intcos^5xsin^3xdx`

Explanation

`intcos^5xsin^3xdx`
=`intcos^5x(1-cos^2x)sinxdx`
[Put cosx=t Then sinxdx=-dt]
=`intt^5(1-t^2).(-dt)=int(t^7-t^5)dt`
=`1/8t^8-1/6cos^6x+C`