`int(sinax-sinbx)/(cosax-cosbx)dx`

Explanation

`int(sinax-sinbx)/(cosax-cosbx)dx`
=`(2sin((a-b)/2) x.cos((a+b)/2) x)/(-2sin((a+b)/2) x.sin((a-b)/2) x)dx`
=`-intcot((a+b)/2)xdx`
=`-2/(a+b) In abs(sin((a+b)/2)x)+C` =`1/k Inabs(sinkx)+C`