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intdx/((2x+5)sqrt(x+2))...

`intdx/((2x+5)sqrt(x+2))`

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Verified by Experts

`intdx/((2x+5)sqrt(x+2))` [Put x+2=t^2`
dx=2tdt]
=`int(2tdt)/([2(t^2-2)+5].t)=int(2dt)/(2t^2+1)`
=`intdt/(t^2+(1/sqrt2)^2)=sqrt2tan^-1(sqrt2t)+C`
=`sqrt2tan^-1(sqrt(2x+4))+C`
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