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intdx/(1+tanx)...

`intdx/(1+tanx)`

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`I=intdx/(1+tanx)`
=`int(cosxdx)/(sinx+cosx)`
=`1/2int((cosx-sinx)+(cosx+sinx))/(sinx+cosx)dx`
=`1/2int(cosx-sinx)/(sinx+cosx)dx+1/2intdx`
=`1/2Inabs(cosx-sinx)+1/2x+c`
`because d/dx(sinx+cosx)=cosx-sinx`
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