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intdx/(e^x-1)...

`intdx/(e^x-1)`

Text Solution

Verified by Experts

`I=intdx/(e^x-1)`
=`inte^-x/(1-e^-x)dx`
Let `1-e^-x=t`
`e^-xdx=dt`
`therefore I=intdt/t`
=`Inabst+c`
=`Inabs(1-e^-x)+c`
=`Inabs((e^x-1)/e^x)+c`
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