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Find the area enclosed by y^2=x^3,x=0,...

Find the area enclosed by
`y^2=x^3,x=0,y=1`

Text Solution

Verified by Experts

Given curve is `y^2=x^3`
`impliesx=y^(2//3)`
It pass through the origin So the required area
`=int_0^1xdy= int_0^1 y^(2/3)dy=[y^(2/3)/(5//3)]_0^1=3/5`
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