Solve the following differential equations.
`dy/dx=e^y`

Explanation

`dy/dx=e^yrArre^(-y)dy=dx`
Integrating we get `inte^(-y)dy=intdx`
`rArr e^(-y)/-1=x+C rArr -e^(-y)+x+C`
`rArrx+e^(-y)+C=0`